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Problem solution · Go

Codeforces 438D — The Child and Sequence

Codeforces 438D — The Child and Sequence: a Go solution using direct simulation. Learn the idea, check the complexity, and read the full code, with credit to EndlessCheng Codeforces Go.

Technique
Direct simulation
Source
EndlessCheng Codeforces Go
Length
119 lines
Start with the idea.

Try the problem first. If you get stuck, read the approach below, then write your own solution. The full code is at the bottom.

Approach

Direct simulation

For Codeforces 438D — The Child and Sequence, the implementation follows the problem’s operations directly while maintaining only the state needed for the next decision.

  1. Translate each rule into one explicit state update.
  2. Maintain the invariant after every processed item.
  3. Return the accumulated state once all relevant input has been handled.

Code notes

  • 119 lines of Go from the credited upstream file 438D.go.
  • The implementation visibly relies on sequence storage, ordered lookup.
  • No explicit loop blocks detected.

Complexity

Count the number and nesting of passes over the input, then include the maintained containers in the memory estimate.

Check the problem constraints before deciding whether this complexity will pass.

Source

Code and credit

This code comes from EndlessCheng Codeforces Go by Σndless (EndlessCheng) and is used under the MIT licence.

Open problem ↗Original source ↗
Full codeCodeforces 438D — The Child and Sequence · GoGo
Use this to learn the idea, then write your own version.
package main import (	"bufio"	. "fmt"	"io") // github.com/EndlessCheng/codeforces-gotype seg38 []struct {	l, r  int	max   int	sum   int64} func (t seg38) set(o, v int) {	t[o].max = v	t[o].sum = int64(v)} func (t seg38) maintain(o int) {	lo, ro := t[o<<1], t[o<<1|1]	t[o].max = max38(lo.max, ro.max)	t[o].sum = lo.sum + ro.sum} func (t seg38) build(a []int, o, l, r int) {	t[o].l, t[o].r = l, r	if l == r {		t.set(o, a[l-1])		return	}	m := (l + r) >> 1	t.build(a, o<<1, l, m)	t.build(a, o<<1|1, m+1, r)	t.maintain(o)} func (t seg38) mod(o, l, r, mod int) {	if t[o].max < mod {		return	}	if t[o].l == t[o].r {		t[o].max %= mod		t[o].sum = int64(t[o].max)		return	}	m := (t[o].l + t[o].r) >> 1	if l <= m {		t.mod(o<<1, l, r, mod)	}	if r > m {		t.mod(o<<1|1, l, r, mod)	}	t.maintain(o)} func (t seg38) update(o, i, v int) {	if t[o].l == t[o].r {		t.set(o, v)		return	}	m := (t[o].l + t[o].r) >> 1	if i <= m {		t.update(o<<1, i, v)	} else {		t.update(o<<1|1, i, v)	}	t.maintain(o)} func (t seg38) query(o, l, r int) (res int64) {	if l <= t[o].l && t[o].r <= r {		return t[o].sum	}	m := (t[o].l + t[o].r) >> 1	if r <= m {		return t.query(o<<1, l, r)	}	if m < l {		return t.query(o<<1|1, l, r)	}	return t.query(o<<1, l, r) + t.query(o<<1|1, l, r)} func CF438D(_r io.Reader, _w io.Writer) {	in := bufio.NewReader(_r)	out := bufio.NewWriter(_w)	defer out.Flush() 	var n, q, op, l, r, mod int	Fscan(in, &n, &q)	a := make([]int, n)	for i := range a {		Fscan(in, &a[i])	}	t := make(seg38, n*4)	t.build(a, 1, 1, n)	for ; q > 0; q-- {		if Fscan(in, &op, &l, &r); op == 1 {			Fprintln(out, t.query(1, l, r))		} else if op == 2 {			Fscan(in, &mod)			t.mod(1, l, r, mod)		} else {			t.update(1, l, r)		}	}} func max38(a, b int) int {	if a > b {		return a	}	return b} //func main() { CF438D(os.Stdin, os.Stdout) }

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