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Problem solution · Go

Codeforces 593E — Strange Calculation and Cats

Codeforces 593E — Strange Calculation and Cats: a Go solution using direct simulation. Learn the idea, check the complexity, and read the full code, with credit to EndlessCheng Codeforces Go.

Technique
Direct simulation
Source
EndlessCheng Codeforces Go
Length
104 lines
Start with the idea.

Try the problem first. If you get stuck, read the approach below, then write your own solution. The full code is at the bottom.

Approach

Direct simulation

For Codeforces 593E — Strange Calculation and Cats, the implementation follows the problem’s operations directly while maintaining only the state needed for the next decision.

  1. Translate each rule into one explicit state update.
  2. Maintain the invariant after every processed item.
  3. Return the accumulated state once all relevant input has been handled.

Code notes

  • 104 lines of Go from the credited upstream file 593E.go.
  • The implementation visibly relies on sequence storage, ordered lookup.
  • No explicit loop blocks detected.

Complexity

Count the number and nesting of passes over the input, then include the maintained containers in the memory estimate.

Check the problem constraints before deciding whether this complexity will pass.

Source

Code and credit

This code comes from EndlessCheng Codeforces Go by Σndless (EndlessCheng) and is used under the MIT licence.

Open problem ↗Original source ↗
Full codeCodeforces 593E — Strange Calculation and Cats · GoGo
Use this to learn the idea, then write your own version.
package main import (	"bufio"	. "fmt"	"io") // https://github.com/EndlessChengconst mod93 = 1_000_000_007 type matrix93 [][]int func newMatrix93(n, m int) matrix93 {	a := make(matrix93, n)	for i := range a {		a[i] = make([]int, m)	}	return a} func (a matrix93) mul(b matrix93) matrix93 {	c := newMatrix93(len(a), len(b[0]))	for i, row := range a {		for k, x := range row {			if x == 0 {				continue			}			for j, y := range b[k] {				c[i][j] = (c[i][j] + x*y) % mod93			}		}	}	return c} func (a matrix93) powMul(n int, f0 matrix93) matrix93 {	res := f0	for ; n > 0; n /= 2 {		if n%2 > 0 {			res = a.mul(res)		}		a = a.mul(a)	}	return res} func cf593E(in io.Reader, _w io.Writer) {	out := bufio.NewWriter(_w)	defer out.Flush()	var n, m, q, tp, x, y, t int	Fscan(in, &n, &m, &q) 	size := n * m	M := newMatrix93(size, size)	set := func(x, y, val int) {		i := x*m + y		M[i][i] = val		if y > 0 {			M[i][i-1] = val		}		if y < m-1 {			M[i][i+1] = val		}		if x > 0 {			M[i][i-m] = val		}		if x < n-1 {			M[i][i+m] = val		}	} 	for i := range n {		for j := range m {			set(i, j, 1)		}	} 	f := newMatrix93(size, 1)	f[0][0] = 1 	pre := 1	for range q {		Fscan(in, &tp, &x, &y, &t)		x--		y-- 		f = M.powMul(t-pre, f)		pre = t 		i := x*m + y		if tp == 1 {			Fprintln(out, f[i][0])		} else if tp == 2 {			f[i][0] = 0			set(x, y, 0)		} else {			set(x, y, 1)		}	}} //func main() { cf593E(bufio.NewReader(os.Stdin), os.Stdout) }

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