- Translate each rule into one explicit state update.
- Maintain the invariant after every processed item.
- Return the accumulated state once all relevant input has been handled.
Code notes
- 94 lines of Go from the credited upstream file 920E.go.
- The implementation visibly relies on sequence storage.
- No explicit loop blocks detected.
Complexity
Count the number and nesting of passes over the input, then include the maintained containers in the memory estimate.
Check the problem constraints before deciding whether this complexity will pass.
Use this to learn the idea, then write your own version.
1package main2 3import (4 "bufio"5 . "fmt"6 "io"7 "sort"8 "strings"9)10 1112func Sol920E(reader io.Reader, writer io.Writer) {13 in := bufio.NewReader(reader)14 out := bufio.NewWriter(writer)15 defer out.Flush()16 var fa []int17 initFa := func(n int) {18 fa = make([]int, n)19 for i := range fa {20 fa[i] = i21 }22 }23 var find func(int) int24 find = func(x int) int {25 if fa[x] != x {26 fa[x] = find(fa[x])27 }28 return fa[x]29 }30 merge := func(from, to int) { fa[find(from)] = find(to) }31 same := func(x, y int) bool { return find(x) == find(y) }32 33 var n, m, v, w int34 Fscan(in, &n, &m)35 g := make([][]int, n)36 for ; m > 0; m-- {37 Fscan(in, &v, &w)38 v--39 w--40 g[v] = append(g[v], w)41 g[w] = append(g[w], v)42 }43 44 maxDeg0, maxDeg0V := 0, 045 for v, edges := range g {46 if deg0 := n - 1 - len(edges); deg0 > maxDeg0 {47 maxDeg0 = deg048 maxDeg0V = v49 }50 }51 if maxDeg0 == 0 {52 Fprintln(out, n)53 Fprintln(out, strings.Repeat("1 ", n))54 return55 }56 57 merge0 := func(v int, edges []int) {58 vs := map[int]bool{v: true}59 for _, w := range edges {60 vs[w] = true61 }62 for i := 0; i < n; i++ {63 if !vs[i] {64 merge(i, v)65 }66 }67 }68 initFa(n)69 merge0(maxDeg0V, g[maxDeg0V])70 for v, edges := range g {71 if !same(v, maxDeg0V) {72 merge0(v, edges)73 }74 }75 76 cnt := map[int]int{}77 for i := range fa {78 cnt[find(i)]++79 }80 values := make([]int, 0, len(cnt))81 for _, v := range cnt {82 values = append(values, v)83 }84 sort.Ints(values)85 Fprintln(out, len(values))86 for _, v := range values {87 Fprint(out, v, " ")88 }89}90 91929394