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Problem solution · Python

ABC341 E — Alternating String

ABC341 E — Alternating String: a Python solution using sorting and greedy selection. Learn the idea, check the complexity, and read the full code, with credit to KATO-Hiro AtCoder Solutions.

Technique
Sorting and greedy selection
Source
KATO-Hiro AtCoder Solutions
Length
227 lines
Start with the idea.

Try the problem first. If you get stuck, read the approach below, then write your own solution. The full code is at the bottom.

Approach

Sorting and greedy selection

For ABC341 E — Alternating String, the implementation first exposes a useful order, then scans that order while making locally justified choices.

  1. Choose the key that reveals the greedy or grouping structure.
  2. Sort the relevant records by that key.
  3. Scan in order, maintaining the invariant that makes each local choice safe.

Code notes

  • 227 lines of Python from the credited upstream file abc341_e.py.
  • The implementation visibly relies on sequence storage, ordered lookup.
  • No explicit loop blocks detected.

Complexity

Sorting is typically the dominant term unless the subsequent scan uses a more expensive nested operation.

Check the problem constraints before deciding whether this complexity will pass.

Source

Code and credit

This code comes from KATO-Hiro AtCoder Solutions by KATO-Hiro and is used under the CC0-1.0 licence.

Open problem ↗Original source ↗
Full codeABC341 E — Alternating String · PythonPython
Use this to learn the idea, then write your own version.
# -*- coding: utf-8 -*- import mathfrom bisect import bisect_left, bisect_rightfrom typing import Generic, Iterable, Iterator, List, TypeVar, Union T = TypeVar("T")  class SortedSet(Generic[T]):    """Sorted set (set) in C++.     See:    https://qiita.com/tatyam/items/492c70ac4c955c055602    https://github.com/tatyam-prime/SortedSet/blob/main/SortedSet.py    """     BUCKET_RATIO = 50    REBUILD_RATIO = 170     def _build(self, a=None) -> None:        "Evenly divide `a` into buckets."        if a is None:            a = list(self)         size = self.size = len(a)        bucket_size = int(math.ceil(math.sqrt(size / self.BUCKET_RATIO)))        self.a = [            a[size * i // bucket_size : size * (i + 1) // bucket_size]            for i in range(bucket_size)        ]     def __init__(self, a: Iterable[T] = []) -> None:        """Make a new SortedSet from iterable.        / O(N) if sorted and unique / O(N log N)        """        a = list(a)         if not all(a[i] < a[i + 1] for i in range(len(a) - 1)):  # type: ignore            a = sorted(set(a))  # type: ignore         self._build(a)     def __iter__(self) -> Iterator[T]:        for i in self.a:            for j in i:                yield j  # type: ignore     def __reversed__(self) -> Iterator[T]:        for i in reversed(self.a):            for j in reversed(i):                yield j     def __len__(self) -> int:        return self.size     def __repr__(self) -> str:        return "SortedSet" + str(self.a)     def __str__(self) -> str:        s = str(list(self))        return "{" + s[1 : len(s) - 1] + "}"     def _find_bucket(self, x: T) -> List[T]:        "Find the bucket which should contain x. self must not be empty."        for a in self.a:            if x <= a[-1]:  # type: ignore                return a        return a     def __contains__(self, x: T) -> bool:        if self.size == 0:            return False         a = self._find_bucket(x)        i = bisect_left(a, x)  # type: ignore         return i != len(a) and a[i] == x     def add(self, x: T) -> bool:        "Add an element and return True if added. / O(√N)"        if self.size == 0:            self.a = [[x]]            self.size = 1            return True         a = self._find_bucket(x)        i = bisect_left(a, x)  # type: ignore         if i != len(a) and a[i] == x:            return False         a.insert(i, x)        self.size += 1         if len(a) > len(self.a) * self.REBUILD_RATIO:            self._build()         return True     def discard(self, x: T) -> bool:        "Remove an element and return True if removed. / O(√N)"        if self.size == 0:            return False         a = self._find_bucket(x)        i = bisect_left(a, x)  # type: ignore         if i == len(a) or a[i] != x:            return False         a.pop(i)        self.size -= 1         if len(a) == 0:            self._build()        return True     def lt(self, x: T) -> Union[T, None]:        "Find the largest element < x, or None if it doesn't exist."        for a in reversed(self.a):            if a[0] < x:  # type: ignore                return a[bisect_left(a, x) - 1]  # type: ignore        return None     def le(self, x: T) -> Union[T, None]:        "Find the largest element <= x, or None if it doesn't exist."        for a in reversed(self.a):            if a[0] <= x:  # type: ignore                return a[bisect_right(a, x) - 1]  # type: ignore        return None     def gt(self, x: T) -> Union[T, None]:        "Find the smallest element > x, or None if it doesn't exist."        for a in self.a:            if a[-1] > x:  # type: ignore                return a[bisect_right(a, x)]  # type: ignore        return None     def ge(self, x: T) -> Union[T, None]:        "Find the smallest element >= x, or None if it doesn't exist."        for a in self.a:            if a[-1] >= x:  # type: ignore                return a[bisect_left(a, x)]  # type: ignore        return None     def __getitem__(self, x: int) -> T:        "Return the x-th element, or IndexError if it doesn't exist."        if x < 0:            x += self.size        if x < 0:            raise IndexError         for a in self.a:            if x < len(a):                return a[x]  # type: ignore             x -= len(a)        raise IndexError     def index(self, x: T) -> int:        "Count the number of elements < x."        ans = 0         for a in self.a:            if a[-1] >= x:  # type: ignore                return ans + bisect_left(a, x)  # type: ignore            ans += len(a)        return ans     def index_right(self, x: T) -> int:        "Count the number of elements <= x."        ans = 0         for a in self.a:            if a[-1] > x:  # type: ignore                return ans + bisect_right(a, x)  # type: ignore            ans += len(a)        return ans  def main():    import sys     input = sys.stdin.readline     n, q = map(int, input().split())    s = input().rstrip()    t = SortedSet()     # 文字列を0-indexedで考える    # 隣同士の文字の一致・不一致を管理するときのインデックスは、文字列の0文字目の左側を0番目とする    for i in range(n - 1):        if s[i] == s[i + 1]:            t.add(i + 1)     # 右端の処理    inf = 10**9    t.add(inf)     for _ in range(q):        type, li, ri = map(int, input().split())         if type == 1:            li -= 1             if li in t:                t.discard(li)            else:                t.add(li)             if ri in t:                t.discard(ri)            else:                t.add(ri)        else:            value = t.ge(li)             if value < ri:                print("No")            else:                print("Yes")  if __name__ == "__main__":    main()

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