- Give each element a component representative.
- Merge representatives when a connection is accepted.
- Answer connectivity or component queries from the compressed representatives.
Code notes
- 148 lines of Python from the credited upstream file abc401_e.py.
- The implementation visibly relies on sequence storage, ordered lookup.
- No explicit loop blocks detected.
Complexity
Account for every find and union operation; with path compression and ranked merging, the amortized cost is nearly constant per operation.
Check the problem constraints before deciding whether this complexity will pass.
Use this to learn the idea, then write your own version.
12 3from typing import List4 5 6class UnionFind:7 """Represents a data structure that tracks a set of elements partitioned8 into a number of disjoint (non-overlapping) subsets.9 10 Landau notation: O(α(n)), where α(n) is the inverse Ackermann function.11 12 See:13 https:www.youtube.com/watch?v=zV3Ul2pA2Fw14 https:en.wikipedia.org/wiki/Disjoint-set_data_structure15 https:atcoder.jp/contests/abc120/submissions/444494216 https:atcoder.jp/contests/abc292/submissions/3941007517 https:github.com/not522/ac-library-python/blob/master/atcoder/dsu.py18 """19 20 def __init__(self, number_count: int) -> None:21 """22 Args:23 number_count: The size of elements (greater than 2).24 """25 self.number_count = number_count26 self.parent_numbers = [-1 for _ in range(number_count)]27 self.edge_count = [0 for _ in range(number_count)]28 self.group_count = number_count29 30 def find_root(self, number: int) -> int:31 """Follows the chain of parent pointers from number up the tree until32 it reaches a root element, whose parent is itself.33 Args:34 number: The trees id (0-index).35 36 Returns:37 The index of a root element.38 """39 if self.parent_numbers[number] < 0:40 return number41 42 self.parent_numbers[number] = self.find_root(self.parent_numbers[number])43 return self.parent_numbers[number]44 45 def get_group_size(self, number: int) -> int:46 """47 Args:48 number: The trees id (0-index).49 50 Returns:51 The size of group.52 """53 return -self.parent_numbers[self.find_root(number)]54 55 def is_same_group(self, number_x: int, number_y: int) -> bool:56 """Represents the roots of tree number_x and number_y are in the same57 group.58 Args:59 number_x: The trees x (0-index).60 number_y: The trees y (0-index).61 """62 return self.find_root(number_x) == self.find_root(number_y)63 64 def merge_if_needs(self, number_x: int, number_y: int) -> bool:65 """Uses find_root to determine the roots of the tree number_x and66 number_y belong to. If the roots are distinct, the trees are combined67 by attaching the roots of one to the root of the other.68 Args:69 number_x: The trees x (0-index).70 number_y: The trees y (0-index).71 """72 x = self.find_root(number_x)73 y = self.find_root(number_y)74 75 self.edge_count[x] += 176 77 if x == y:78 return False79 80 self.group_count -= 181 82 if self.parent_numbers[x] > self.parent_numbers[y]:83 x, y = y, x84 85 self.parent_numbers[x] += self.parent_numbers[y]86 self.parent_numbers[y] = x87 self.edge_count[x] += self.edge_count[y]88 return True89 90 def get_roots(self) -> List[int]:91 return [i for i, x in enumerate(self.parent_numbers) if x < 0]92 93 def get_groups(self) -> List[List[int]]:94 roots: List[int] = [self.find_root(i) for i in range(self.number_count)]95 groups: List[List[int]] = [[] for _ in range(self.number_count)]96 97 for i in range(self.number_count):98 groups[roots[i]].append(i)99 100 return list(filter(lambda g: g, groups))101 102 def get_edge_count(self, number: int) -> int:103 return self.edge_count[number]104 105 def get_group_count(self) -> int:106 return self.group_count107 108 109def main():110 import sys111 112 input = sys.stdin.readline113 114 n, m = map(int, input().split())115 graph = [[] for _ in range(n)]116 117 for _ in range(m):118 ai, bi = map(int, input().split())119 ai -= 1120 bi -= 1121 122 graph[ai].append(bi)123 graph[bi].append(ai)124 125 uf_small = UnionFind(n)126 uf_large = UnionFind(n)127 ans = list()128 129 for i in range(n):130 for j in graph[i]:131 if i > j:132 uf_small.merge_if_needs(i, j)133 else:134 uf_large.merge_if_needs(i, j)135 136 k = i + 1137 138 if uf_small.get_group_size(0) == k:139 ans += [uf_large.get_group_size(0) - k]140 else:141 ans += [-1]142 143 print(*ans, sep="\n")144 145 146if __name__ == "__main__":147 main()148