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Problem solution · SQL

Calculate Parking Fees and Duration

Calculate Parking Fees and Duration: a SQL solution using relational aggregation. Learn the idea, check the complexity, and read the full code, with credit to walkccc LeetCode Solutions.

Technique
Relational aggregation
Source
walkccc LeetCode Solutions
Length
38 lines
Start with the idea.

Try the problem first. If you get stuck, read the approach below, then write your own solution. The full code is at the bottom.

Approach

Relational aggregation

For Calculate Parking Fees and Duration, the query transforms and combines relational rows, then filters or aggregates them into the requested result.

  1. Identify the source rows and join keys.
  2. Apply filters before aggregation when possible.
  3. Group, rank, or project the final columns required by the result.

Code notes

  • 38 lines of SQL from the credited upstream file 3166.sql.
  • The implementation keeps its working state in language-native values and containers.
  • No explicit loop blocks detected.

Complexity

Review join cardinality, grouping keys, and available indexes when estimating query cost.

Check the problem constraints before deciding whether this complexity will pass.

Source

Code and credit

This code comes from walkccc LeetCode Solutions by P.-Y. Chen (walkccc) and is used under the MIT licence.

Open problem ↗Original source ↗
Full codeCalculate Parking Fees and Duration · SQLSQL
Use this to learn the idea, then write your own version.
WITH  Cars AS (    SELECT      car_id,      SUM(fee_paid) AS total_fee_paid,      SUM(TIMESTAMPDIFF(MINUTE, entry_time, exit_time)) AS total_duration    FROM ParkingTransactions    GROUP BY 1  ),  CarToDurationPerLot AS (    SELECT      car_id,      lot_id,      SUM(TIMESTAMPDIFF(MINUTE, entry_time, exit_time)) AS duration_per_lot    FROM ParkingTransactions    GROUP BY 1, 2  ),  CarToMaxDurationPerLot AS (    SELECT      car_id,      MAX(duration_per_lot) AS max_duration_per_lot    FROM CarToDurationPerLot    GROUP BY 1  )SELECT  Cars.car_id,  Cars.total_fee_paid,  ROUND(Cars.total_fee_paid * 60 / Cars.total_duration, 2) AS avg_hourly_fee,  CarToDurationPerLot.lot_id AS most_time_lotFROM CarsINNER JOIN CarToDurationPerLot  USING (car_id)INNER JOIN CarToMaxDurationPerLot  USING (car_id)WHERE  CarToDurationPerLot.duration_per_lot = CarToMaxDurationPerLot.max_duration_per_lotORDER BY 1;

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