DMOJ · coci20c3p1

COCI '20 Contest 3 #1 Knjige

This C++ solution uses sorting & greedy for DMOJ coci20c3p1 COCI '20 Contest 3 #1 Knjige. Read the reasoning, inspect the code, or try your own test case below.

coci20c3p1Sorting & searchingSorting & greedyC++56 lines
Solution123of 248
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Approach

Sorting & greedy

Knjige move construction and output format match the generated operations.

Sorting & searching

Problem and code

Useful links.

Written by benbenyaojifen. Try the problem first, then compare your approach with the code.

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Implementation

Knjige.cpp

C++

    #include <bits/stdc++.h>
    using namespace std;
    using ll = long long;
    using i128 = __int128;
    const int inf = 1e9;
    const ll INF = 2e18; //❄️
    int main() {
        ios::sync_with_stdio(0); cin.tie(0); 
        int n; cin >> n;
        vector<int> v(n);
        stack<int> l, r;
        for (int i = 0; i < n; i++) {
            cin >> v[i];
        }
        for (int i = v.size() -1; i >= 0; i--) {
            l.push(v[i]);
        }
        sort(v.begin(), v.end());
        int pos = 1;
        vector<string> ans;
        while (pos <= n) {
            int x = v[n - pos];
            int sorted = pos - 1;
            while (l.top() != x) {
                int cur = l.top();
                l.pop();
                ans.push_back("UZMI L L");
                r.push(cur);
                ans.push_back("STAVI L D");
            }
            int hand = l.top();
            l.pop();
            ans.push_back("UZMI L L");
            while (l.size() > sorted) {
                int cur = l.top();
                l.pop();
                ans.push_back("UZMI D L");
                r.push(cur);
                ans.push_back("STAVI D D");
            }
            l.push(hand);
            ans.push_back("STAVI L L");
            while (!r.empty()) {
                int cur = r.top();
                r.pop();
                ans.push_back("UZMI L D");
                l.push(cur);
                ans.push_back("STAVI L L");
            }
            pos++;
        }
        cout << ans.size() << '\n';
        for (int i = 0; i < ans.size(); i++) cout << ans[i] << '\n';
        return 0;
    }
     
        

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