Codeforces · 2211C2

Equal Multisets (Hard Version)

This C++ solution uses mathematical reasoning for Codeforces 2211C2 Equal Multisets (Hard Version). Read the reasoning, inspect the code, or try your own test case below.

2211C2MathMathematical reasoningC++65 lines
Solution084of 248
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Approach

Mathematical reasoning

Equal Multisets (Hard Version) and the residue-class counting construction match the code.

Math

Problem and code

Useful links.

Written by benbenyaojifen. Try the problem first, then compare your approach with the code.

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Implementation

C_2_Equal_Multisets_Hard_Version.cpp

C++

    #include <bits/stdc++.h>
    using namespace std;
    using ll = long long;
    using i128 = __int128;
    const int inf = 1e9;
    const ll INF = 1e18; //❄️
    void solve() {
        int n, k; cin >> n >> k;
        vector<int> a(n), b(n);
        for (int i = 0; i < n; i++) cin >> a[i];
        for (int i = 0; i < n; i++) cin >> b[i];
        vector<int> tar(n + 1), used(n + 1);
        for (int i = 0; i < k; i++) { 
            tar[a[i]]++;
        }
        for (int i = 0; i < k; i++) {
            bool c = 1;
            int f = a[i];
            for (int j = i + k; j < n; j += k) {
                if (a[j] != f) {
                    c = 0; 
                    break;
                }
            }
            if (!c) {
                for (int j = i; j < n; j += k) {
                    if (b[j] != -1 && b[j] != a[j]) {
                        cout << "NO" << '\n';
                        return;
                    }
                }
                used[a[i]]++;
            } else {
                int val = -1;
                for (int j = i; j < n; j += k) {
                    if (b[j] != -1) {
                        if (val == -1) {
                            val = b[j];
                        } else if (val != b[j]) {
                            cout << "NO" << '\n';
                            return;
                        }
                    }
                }
                if (val != -1) {
                    used[val]++;
                }
            }
        }
        for (int i = 1; i <= n; i++) {
            if (used[i] > tar[i]) {
                cout << "NO" << '\n';
                return;
            }
        }
        cout << "YES" << '\n';
    }
    int main() {
        ios::sync_with_stdio(0); cin.tie(0); 
        int t; cin >> t;
        while (t--) {
            solve();
        }
        return 0;
    }
        

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