CSES · 1681

Game Routes

This C++ solution uses dag dynamic programming for CSES 1681 Game Routes. Read the reasoning, inspect the code, or try your own test case below.

1681Dynamic programmingDAG dynamic programmingC++38 lines
Solution096of 248
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Approach

DAG dynamic programming

Game Routes task counts directed routes from 1 to n modulo 1e9+7; the DAG DP matches.

Dynamic programming

Problem and code

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Written by benbenyaojifen. Try the problem first, then compare your approach with the code.

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Implementation

game_routes.cpp

C++

    #include <bits/stdc++.h>
    using namespace std;
    const int mod = 1e9 + 7;
    //idea is to use toposort to ensure that u always before v for every direct edge u - v and then accumulate cnt of paths 
    int main(){
        ios::sync_with_stdio(0);
        cin.tie(0);
        int n, m; cin >> n >> m;
        vector<vector<int>> adj(n + 1);
        vector<int> indegree(n + 1);
        for(int i = 0; i < m; i++){
            int a, b; cin >> a >> b;
            adj[a].push_back(b);
            indegree[b]++;
        }
        queue<int> q;
        vector<int> res;
        for(int i = 0; i < indegree.size(); i++){
            if(indegree[i] == 0) q.push(i);
        }
        while(!q.empty()){
            int node = q.front(); q.pop();
            res.push_back(node);
            for(int nxt : adj[node]){
                if(!--indegree[nxt]) q.push(nxt);
            }
        }
        vector<int> dp(n + 1); dp[1] = 1; // base case
        for(int i = 0; i < res.size(); i++){
            int cur = res[i];
            for(int nxt : adj[cur]){
                dp[nxt] += dp[cur];
                dp[nxt] %= mod;
            }
        }
        cout << dp[n] << '\n';
        return 0;
    }
        

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