DMOJ · sac22cc2p3

Rating Choices

This C++ solution uses graph traversal for DMOJ sac22cc2p3 Rating Choices. Read the reasoning, inspect the code, or try your own test case below.

sac22cc2p3Graphs & treesGraph traversalC++31 lines
Solution170of 248
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Approach

Graph traversal

Rating Choices matches the directed choice tree, starting rating, and maximum achievable rating computation.

Graphs & trees

Problem and code

Useful links.

Written by benbenyaojifen. Try the problem first, then compare your approach with the code.

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Implementation

P_3_Rating_Choices.cpp

C++

    #include <bits/stdc++.h>
    using namespace std;
    using ll = long long;
    using i128 = __int128;
    const int inf = 1e9;
    const long long INF = 1e17; //❄️
    int main() {
        ios::sync_with_stdio(0); cin.tie(0); 
        int n; ll cur; cin >> n >> cur;
        ll node = (1 << (n + 1)) - 1, m = (1 << n) - 1;
        vector<array<pair<int, int>, 2>> adj(node + 1);
        vector<bool> leaf(node + 1);
        for (int i = 0; i < m; i++) {
            int u, v, w, d; cin >> u >> v >> w >> d;
            leaf[u] = 1; // not leaf
            adj[u][0] = {v, d}; //take
            adj[u][1] = {w, 0}; //skip
        }
        ll ans = -INF;
        auto dfs = [&] (auto &&self, int u, ll best) -> void {
            if (!leaf[u]) { //is leaf
                ans = max(ans, best);
                return;
            }
            self(self, adj[u][0].first, best + adj[u][0].second);
            self(self, adj[u][1].first, best + adj[u][1].second);
        };
        dfs(dfs, 1, cur);
        cout << ans << '\n';
        return 0;
    }
        

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