DMOJ · sssp

Single Source Shortest Path

This C++ solution uses shortest path for DMOJ sssp Single Source Shortest Path. Read the reasoning, inspect the code, or try your own test case below.

ssspGraphs & treesShortest pathC++34 lines
Solution191of 248
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Approach

Shortest path

Single the code Shortest Path matches the undirected weighted graph and one distance output per vertex from node 1.

Graphs & trees

Problem and code

Useful links.

Written by benbenyaojifen. Try the problem first, then compare your approach with the code.

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Implementation

Single_Source_Shortest_Path.cpp

C++

    #include <bits/stdc++.h>
    using namespace std;
    typedef long long ll;
    const int inf = 1e9;
    const long long INF = 1e17; //❄️
    int main() {
        ios::sync_with_stdio(0); cin.tie(0);
        int n, m; cin >> n >> m;
        vector<vector<pair<int, int>>> adj(n + 1);
        for (int i = 0; i < m; i++) {
            int u, v, w; cin >> u >> v >> w;
            adj[u].emplace_back(w, v);
            adj[v].emplace_back(w, u);
        }
        vector<int> dist(n + 1, inf);
        dist[1] = 0;
        priority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>> pq;
        pq.push({0, 1});
        while (!pq.empty()) {
            auto[w, u] = pq.top(); pq.pop();
            if (w > dist[u]) continue;
            for (auto &[wt, v] : adj[u]) {
                if (dist[v] > wt + w) {
                    dist[v] = wt + w;
                    pq.push({dist[v], v});
                }
            }
        }
        for (int i = 1; i <= n; i++) {
            if (dist[i] == inf) cout << -1 << '\n';
            else cout << dist[i] << '\n';
        }
        return 0;
    }
        

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