DMOJ · ioi94p1

The Triangle

This C++ solution uses dynamic programming for DMOJ ioi94p1 The Triangle. Read the reasoning, inspect the code, or try your own test case below.

ioi94p1Dynamic programmingC++38 lines
Solution221of 248
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Approach

Dynamic programming

The Triangle matches the triangular input and maximum top-to-bottom path-sum dynamic programming.

Dynamic programming

Problem and code

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Written by benbenyaojifen. Try the problem first, then compare your approach with the code.

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Implementation

P_1_The_Triangle.cpp

C++

    #include <bits/stdc++.h>
    using namespace std;
    using ll = long long;
    using i128 = __int128;
    const int inf = 1e9;
    const ll INF = 1e18; //❄️
    int main() {
        ios::sync_with_stdio(0); cin.tie(0); 
        int n; cin >> n;
        vector<vector<int>> v(n);
        for (int i = 1; i <= n; i++) {
            for (int j = 0; j < i; j++) {
                int x; cin >> x;
                v[i - 1].push_back(x);
            }
        }
        vector<vector<int>> dp(n);
        for (int i = 0; i < n; i++) {
            dp[i].assign(i + 1, 0);
        }
        dp[0][0] = v[0][0];
        for (int i = 1; i < n; i++) {
            for (int j = 0; j <= i; j++) {
                if (j < i) {
                    dp[i][j] = max(dp[i][j], dp[i - 1][j] + v[i][j]);
                }
                if (j > 0) {
                    dp[i][j] = max(dp[i][j], dp[i - 1][j - 1] + v[i][j]);
                }
            }
        }
        int ans = 0;
        for (int i = 0; i < n; i++) {
            ans = max(ans, dp[n - 1][i]);
        }
        cout << ans << '\n';
        return 0;
    }
        

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