DMOJ · utso24p2

UTS Open '24 P2 - Happy Gifts

This C++ solution uses greedy for DMOJ utso24p2 UTS Open '24 P2 - Happy Gifts. Read the reasoning, inspect the code, or try your own test case below.

utso24p2GreedyC++35 lines
Solution106of 248
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Approach

Greedy

Happy Gifts costs for positive and negative gifts match the greedy counting implementation.

Greedy

Problem and code

Useful links.

Written by benbenyaojifen. Try the problem first, then compare your approach with the code.

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Implementation

happy_gifts.cpp

C++

    #include <bits/stdc++.h>
     
    using namespace std;
     
    typedef long long ll;
     
    int main(){
        ios::sync_with_stdio(0);
        cin.tie(0);
        int n, k;
        cin >> n >> k;
        vector<int> positive, negative;
        for(int i = 0; i < n; i++){
            int val; 
            cin >> val;
            if(val < 0) negative.push_back(-val);
            else positive.push_back(val);
        }
        vector<ll> psa(positive.size() + 1);
        sort(positive.begin(), positive.end(), greater<int>());
        sort(negative.begin(), negative.end(), greater<int>());
        int size = positive.size();
        for(int i = 1; i <= size; i++){
            psa[i] = psa[i - 1] + positive[i - 1];
        }
        ll ans = psa[min(k, size)];
        ll negative_sum = 0;
        for(int i = 0; i < negative.size() && k >= 2; i++){
            negative_sum += negative[i];
            k -= 2;
            ans = max(ans, negative_sum + psa[min(k, size)]);
        }  
        cout << ans <<'\n';
        return 0;
    }
        

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