DMOJ · vmss15c1p4

VMSS '15 #4 - Frank and Roads

This C++ solution uses dijkstra's algorithm for DMOJ vmss15c1p4 VMSS '15 #4 - Frank and Roads. Read the reasoning, inspect the code, or try your own test case below.

vmss15c1p4Graphs & treesDijkstra's algorithmC++39 lines
Solution093of 248
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Approach

Dijkstra's algorithm

Frank and Roads asks for destinations reachable from home within T; the directed Dijkstra and count match.

Graphs & trees

Problem and code

Useful links.

Written by benbenyaojifen. Try the problem first, then compare your approach with the code.

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Implementation

4_Frank_and_Roads.cpp

C++

    #include <bits/stdc++.h>
    using namespace std;
    typedef long long ll;
    const int inf = 1e9;
    const long long INF = 1e17; //❄️
    int main() {
        ios::sync_with_stdio(0); cin.tie(0); 
        int t, n, m, g; cin >> t >> n >> m >> g;
        unordered_set<int> d;
        for (int i = 0; i < g; i++) {
            int x; cin >> x;
            d.insert(x);
        }
        vector<vector<pair<int, int>>> adj(n + 1);
        for (int i = 0; i < m; i++) {
            int u, v, w; cin >> u >> v >> w;
            adj[u].emplace_back(w, v);
        }
        vector<int> dist(n + 1, inf);
        dist[0] = 0;
        priority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>> pq;
        pq.push({0, 0});
        while (!pq.empty()) {
            auto[w, u] = pq.top(); pq.pop();
            if (w > dist[u]) continue;
            for (auto[wt, v] : adj[u]) {
                if (dist[v] > wt + w) {
                    dist[v] = wt + w;
                    pq.push({dist[v], v});
                }
            }
        }
        int ans = 0;
        for (int i = 1; i <= n; i++) {
            if (d.count(i) && dist[i] <= t) ans++;
        }
        cout << ans << '\n';
        return 0;
    }
        

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