DMOJ · yac8p1

Yet Another Contest 8 P1 - Permutation Sorting

This C++ solution uses simulation for DMOJ yac8p1 Yet Another Contest 8 P1 - Permutation Sorting. Read the reasoning, inspect the code, or try your own test case below.

yac8p1Arrays & prefix sumsSimulationC++30 lines
Solution161of 248
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Approach

Simulation

Permutation Sorting minimum cost is the union length of intervals from i to pos(i); the difference-array solution matches the editorial criterion.

Arrays & prefix sums

Problem and code

Useful links.

Written by benbenyaojifen. Try the problem first, then compare your approach with the code.

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Implementation

P_1_Permutation_Sorting.cpp

C++

    #include <bits/stdc++.h>
    using namespace std;
    using ll = long long;
    using i128 = __int128;
    const int inf = 1e9;
    const long long INF = 1e17; //❄️
    int main() {
        ios::sync_with_stdio(0); cin.tie(0); 
        int n; cin >> n;
        vector<int> v(n + 1), pos(n + 1);
        for (int i = 1; i <= n; i++) {
            cin >> v[i];
            pos[v[i]] = i;
        }
        vector<int> diff(n + 1);
        for (int i = 1; i <= n; i++) {
            if (pos[i] != i) {
                int l = min(i, pos[i]), r = max(i, pos[i]);
                diff[l]++;
                diff[r + 1]--;
            }
        }
        int ans = 0;
        for (int i = 1; i <= n; i++) {
            diff[i] += diff[i - 1];
            if (diff[i] > 0) ans++;
        }
        cout << ans << '\n';
        return 0;
    }
        

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