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Problem solution · Java

Maximum Profitable Triplets With Increasing Prices I

Maximum Profitable Triplets With Increasing Prices I: a Java solution using direct simulation. Learn the idea, check the complexity, and read the full code, with credit to walkccc LeetCode Solutions.

Technique
Direct simulation
Source
walkccc LeetCode Solutions
Length
53 lines
Start with the idea.

Try the problem first. If you get stuck, read the approach below, then write your own solution. The full code is at the bottom.

Approach

Direct simulation

For Maximum Profitable Triplets With Increasing Prices I, the implementation follows the problem’s operations directly while maintaining only the state needed for the next decision.

  1. Translate each rule into one explicit state update.
  2. Maintain the invariant after every processed item.
  3. Return the accumulated state once all relevant input has been handled.

Code notes

  • 53 lines of Java from the credited upstream file 2907.java.
  • The implementation visibly relies on sequence storage.
  • 3 loop blocks detected.

Complexity

Count the number and nesting of passes over the input, then include the maintained containers in the memory estimate.

Check the problem constraints before deciding whether this complexity will pass.

Source

Code and credit

This code comes from walkccc LeetCode Solutions by P.-Y. Chen (walkccc) and is used under the MIT licence.

Open problem ↗Original source ↗
Full codeMaximum Profitable Triplets With Increasing Prices I · JavaJava
Use this to learn the idea, then write your own version.
class FenwickTree {  public FenwickTree(int n) {    vals = new int[n + 1];  }   public void maximize(int i, int val) {    while (i < vals.length) {      vals[i] = Math.max(vals[i], val);      i += lowbit(i);    }  }   public int get(int i) {    int res = 0;    while (i > 0) {      res = Math.max(res, vals[i]);      i -= lowbit(i);    }    return res;  }   private int[] vals;   private static int lowbit(int i) {    return i & -i;  }} class Solution {  public int maxProfit(int[] prices, int[] profits) {    final int maxPrice = Arrays.stream(prices).max().getAsInt();    int ans = -1;    FenwickTree maxProfitTree1 = new FenwickTree(maxPrice);    FenwickTree maxProfitTree2 = new FenwickTree(maxPrice);     for (int i = 0; i < prices.length; ++i) {      final int price = prices[i];      final int profit = profits[i];      // max(profits[i])      final int maxProfit1 = maxProfitTree1.get(price - 1);      // max(proftis[i]) + max(profits[j])      final int maxProfit2 = maxProfitTree2.get(price - 1);      maxProfitTree1.maximize(price, profit);      if (maxProfit1 > 0)        maxProfitTree2.maximize(price, profit + maxProfit1);      if (maxProfit2 > 0)        ans = Math.max(ans, profit + maxProfit2);    }     return ans;  }}

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