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Problem solution · Python

Minimum Cost to Make Array Equalindromic

Minimum Cost to Make Array Equalindromic: a Python solution using sorting and greedy selection. Learn the idea, check the complexity, and read the full code, with credit to walkccc LeetCode Solutions.

Technique
Sorting and greedy selection
Source
walkccc LeetCode Solutions
Length
23 lines
Start with the idea.

Try the problem first. If you get stuck, read the approach below, then write your own solution. The full code is at the bottom.

Approach

Sorting and greedy selection

For Minimum Cost to Make Array Equalindromic, the implementation first exposes a useful order, then scans that order while making locally justified choices.

  1. Choose the key that reveals the greedy or grouping structure.
  2. Sort the relevant records by that key.
  3. Scan in order, maintaining the invariant that makes each local choice safe.

Code notes

  • 23 lines of Python from the credited upstream file 2967.py.
  • The implementation visibly relies on sequence storage.
  • No explicit loop blocks detected.

Complexity

Sorting is typically the dominant term unless the subsequent scan uses a more expensive nested operation.

Check the problem constraints before deciding whether this complexity will pass.

Source

Code and credit

This code comes from walkccc LeetCode Solutions by P.-Y. Chen (walkccc) and is used under the MIT licence.

Open problem ↗Original source ↗
Full codeMinimum Cost to Make Array Equalindromic · PythonPython
Use this to learn the idea, then write your own version.
class Solution:  def minimumCost(self, nums: list[int]) -> int:    nums.sort()    median = nums[len(nums) // 2]    nextPalindrome = self._getPalindrome(median, delta=1)    prevPalindrome = self._getPalindrome(median, delta=-1)    return min(self._cost(nums, nextPalindrome),               self._cost(nums, prevPalindrome))   def _cost(self, nums: list[int], palindrome: int) -> int:    """Returns the cost to change all the numbers to `palindrome`."""    return sum(abs(palindrome - num) for num in nums)   def _getPalindrome(self, num: int, delta: int) -> int:    """Returns the palindrome `p`, where p = num + a * delta and a > 0."""    while not self._isPalindrome(num):      num += delta    return num   def _isPalindrome(self, num: int) -> int:    original = str(num)    return original == original[::-1]

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