- Translate each rule into one explicit state update.
- Maintain the invariant after every processed item.
- Return the accumulated state once all relevant input has been handled.
Code notes
- 34 lines of Python from the credited upstream file 2456.py.
- The implementation visibly relies on sequence storage.
- No explicit loop blocks detected.
Complexity
Count the number and nesting of passes over the input, then include the maintained containers in the memory estimate.
Check the problem constraints before deciding whether this complexity will pass.
Use this to learn the idea, then write your own version.
1class Creator:2 def __init__(self, popularity: int, videoId: str, maxView: int):3 self.popularity = popularity 4 self.videoId = videoId 5 self.maxView = maxView 6 7 8class Solution:9 def mostPopularCreator(self, creators: list[str],10 ids: list[str],11 views: list[int]) -> list[list[str]]:12 ans = []13 maxPopularity = 014 nameToCreator = {}15 16 for name, id, view in zip(creators, ids, views):17 if name not in nameToCreator:18 nameToCreator[name] = Creator(view, id, view)19 maxPopularity = max(maxPopularity, view)20 continue21 creator = nameToCreator[name]22 creator.popularity += view23 maxPopularity = max(maxPopularity, creator.popularity)24 if (creator.maxView < view or25 creator.maxView == view and creator.videoId > id):26 creator.videoId = id27 creator.maxView = view28 29 for name, creator in nameToCreator.items():30 if creator.popularity == maxPopularity:31 ans.append([name, creator.videoId])32 33 return ans34