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Problem solution · Python

Zuma Game

Zuma Game: a Python solution using depth-first search. Learn the idea, check the complexity, and read the full code, with credit to walkccc LeetCode Solutions.

Technique
Depth-first search
Source
walkccc LeetCode Solutions
Length
37 lines
Start with the idea.

Try the problem first. If you get stuck, read the approach below, then write your own solution. The full code is at the bottom.

Approach

Depth-first search

For Zuma Game, the implementation follows one branch at a time, making it suitable for components, trees, backtracking, or dependency exploration.

  1. Define the state carried into one recursive or stack frame.
  2. Mark or choose the current state before exploring children.
  3. Combine child results or undo the choice when the branch finishes.

Code notes

  • 37 lines of Python from the credited upstream file 488.py.
  • The implementation visibly relies on ordered lookup.
  • No explicit loop blocks detected, together with recursive traversal.

Complexity

Count unique states for graph traversal; for backtracking, count the branching factor and maximum depth.

Check the problem constraints before deciding whether this complexity will pass.

Source

Code and credit

This code comes from walkccc LeetCode Solutions by P.-Y. Chen (walkccc) and is used under the MIT licence.

Open problem ↗Original source ↗
Full codeZuma Game · PythonPython
Use this to learn the idea, then write your own version.
class Solution:  def findMinStep(self, board: str, hand: str) -> int:    def deDup(board):      start = 0  # the start index of a color sequenece      for i, c in enumerate(board):        if c != board[start]:          if i - start >= 3:            return deDup(board[:start] + board[i:])          start = i  # Meet a new sequence.      return board     @functools.lru_cache(None)    def dfs(board: str, hand: str):      board = deDup(board)      if board == '#':        return 0       boardSet = set(board)      # hand that is in board      hand = ''.join(h for h in hand if h in boardSet)      if not hand:  # infeasible        return math.inf       ans = math.inf       for i in range(len(board)):        for j, h in enumerate(hand):          # Place hs[j] in board[i].          newHand = hand[:j] + hand[j + 1:]          newBoard = board[:i] + h + board[i:]          ans = min(ans, 1 + dfs(newBoard, newHand))       return ans     ans = dfs(board + '#', hand)    return -1 if ans == math.inf else ans

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