DMOJ · pacnw16a

Alphabet

This C++ solution uses longest increasing subsequence for DMOJ pacnw16a Alphabet. Read the reasoning, inspect the code, or try your own test case below.

pacnw16aSorting & searchingLongest increasing subsequenceC++21 lines
Solution011of 248
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Approach

Longest increasing subsequence

Alphabet asks for the minimum letters needed to complete an alphabet subsequence; the code computes 26 minus the LIS length.

Sorting & searching

Problem and code

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Written by benbenyaojifen. Try the problem first, then compare your approach with the code.

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Implementation

Alphabet.cpp

C++

    #include <bits/stdc++.h>
    using namespace std;
    using ll = long long;
    using i128 = __int128;
    const int inf = 1e9;
    const ll INF = 1e18; //❄️
    int main() {
        ios::sync_with_stdio(0); cin.tie(0); 
        string s; cin >> s;
        vector<int> ans;
        for (int i = 0; i < s.size(); i++) {
            if (ans.empty() || s[i] - 'a'> ans.back()) {
                ans.push_back(s[i] - 'a');
            } else {
                int pos = lower_bound(ans.begin(), ans.end(), s[i] - 'a') - ans.begin();
                ans[pos] = s[i] - 'a';
            }
        }
        cout << 26 - ans.size() << '\n';
        return 0;
    }
        

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