Codeforces · 2195C

Dice Roll Sequence

This C++ solution uses dynamic programming for Codeforces 2195C Dice Roll Sequence. Read the reasoning, inspect the code, or try your own test case below.

2195CDynamic programmingC++48 lines
Solution074of 248
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Approach

Dynamic programming

Dice Roll Sequence adjacency restrictions and minimum-change objective match the code's six-face dynamic programming.

Dynamic programming

Problem and code

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Written by benbenyaojifen. Try the problem first, then compare your approach with the code.

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Implementation

C_Dice_Roll_Sequence.cpp

C++

    #include <bits/stdc++.h>
    using namespace std;
    using ll = long long;
    const int inf = 1e9;
    const long long INF = 1e17; //❄️
    void solve() {
        int n; cin >> n;
        vector<int> v(n + 1);
        for (int i = 1; i <= n; i++) {
            cin >> v[i];
        }
        bool adj[7][7] = {};
        for (int i = 1; i <= 6; i++) {
            for (int j = 1; j <= 6; j++) {
                if (i != j && 7 - i != j) adj[i][j] = 1;
            }
        }
        vector<int> dp(7, inf), ndp(7, inf);
        for (int i = 1; i <= 6; i++) {
            dp[i] = (v[1] == i ? 0 : 1);
        }
        for (int i = 2; i <= n; i++) {
            fill(ndp.begin(), ndp.end(), inf);
            for (int j = 1; j <= 6; j++) {
                int best = inf;
                for (int k = 1; k <= 6; k++) {
                    if (adj[j][k]) {
                        best = min(best, dp[k]);
                    } 
                }
                ndp[j] = best + (v[i] == j ? 0 : 1);
            }
            swap(dp, ndp);
        }
        int ans = inf;
        for (int i = 1; i <= 6; i++) {
            ans = min(ans, dp[i]);
        }
        cout << ans << '\n';
    }
    int main() {
        ios::sync_with_stdio(0); cin.tie(0); 
        int t; cin >> t;
        while (t--) {
            solve();
        }
        return 0;
    }
        

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